The Angle Between The Pair Of Straight Lines 3x 2 4xy 3y 2 0 Is
Combine 2xy and 4xy to get 2xy x^ {2}\left (2y\right)xy^ {2}=0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction The differential equation, find a particular solution satisfying the given condition dy/dx = 4xy^2, it being given that y = 1 when x = 0 asked in Differential Equations by Devakumari ( 523k points)
(x+y)^2-4xy formula
(x+y)^2-4xy formula-Precalculus Translation and Rotation of Axis Rotation of a Conic Section 2 Answers Eddie #Advanced Math questions and answers Find the general solution in powers of x of the differential equation (x^2 1)y" 4xy' 2y = 0 Assume the form y (x) = Sigma^infinity _n = 0 c_nx^n Then y' (x) = Sigma^infinity _n = 1 c_nx^n1 y" (x) = Sigma^infinity _n = 2 c_nx^n2 x^2y" (x) = Sigma^infinity _n = 2 c_nx^n y" (x) = Sigma^infinity _n
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Find an answer to your question find area of triangle formed by the lines x^24xyy^2=0 and xy =1 MANKOTIA MANKOTIA Math Secondary School answered Find area of triangle formed by the lines x^24xyy^2=0 and xy =1 2 x2 4xy y2 ,the equation of a pair of straight line representing other two sides of the triangle NowAnswer x^24y^2=4xy x^24y^24xy=0 Using the formula (ab)^2=a^2b^22ab here a=x,b=2y so, (x2y)^2=0 x2y=0 x=2y x/y=2/1Solve the differential equation y''4xy'(24x^(2))y=0 (y two strokes of the second (2nd) order plus 4xy stroke first (1st) order plus (2 plus 4x to the power of (2))y equally 0) various methods for solving and various orders of differential equations THERE'S THE ANSWER!
The equation of the angle bisectors of the lines is x = ± y The line x = − y is perpendicular to x − y = 4 Hence the above is an isosceles triangle with the vertical angle being 6 0 0So it looks like when we have the product of the sum of two things and their difference, the result is the difference in their squares Let's see if we can use this to simplify the left side of our equation $$(x2y)(x2y)=(x)^2(2y)^2$$ Well, if we distribute that $2$ exponent inside the parentheses, we'll get $$(x2y)(x2y)=xFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor
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First solve for y x2y=4 2y = x 4 y = (x 4)/ (2) y = 1/2x 2 Looking at we can see that the equation is in slopeintercept form where the slope is and the yintercept is Since this tells us that the yintercept is Remember the yintercept is the point where the graph intersects with theThe tangent at any point P of a curve C meets the xaxis at Q whose abscissa is positive and OP=OQ O being the origin, the equation of curve C satisfying these conditions may be (1) y^{2}=\frac {1}{4}(14x) (2) y^{2}=\frac {1}{4}(912x) (3)
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